What are the solutions to the equation 0=x^2-0.3x-0.1 ?

The solutions to the equation 0=x^2-0.3x-0.1 are x= 1/2 ,x=-1/5

Find the zeros of 0=x^2-0.3x-0.1

The zeros of 0=x^2-0.3x-0.1 are x= 1/2 ,x=-1/5

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0 = x^{2} - 0.3 x - 0.1

x = \frac{1}{2}, x = - \frac{1}{5}

Decimal Notation

x = 0.5, x = - 0.2

Solution steps

0 = x^{2} - 0.3 x - 0.1

Multiply both sides by

10

0 = 10 x^{2} - 3 x - 1

Switch sides

10 x^{2} - 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 10 ( - 1 )}{2 \cdot 10}

(- 3)^{2} - 4 \cdot 10 (- 1) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 10}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 10}

x = \frac{- ( - 3 ) + 7}{2 \cdot 10} : \frac{1}{2}

x = \frac{- ( - 3 ) - 7}{2 \cdot 10} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{5}

a, a^{2} + b^{2} + c^{2} = 2015

3 x^{2} - 11 x - 1 = 3

x^{2} - 39 = - 2 x + 9

- t^{2} - 7 t - 4 = - 2 t^{2}

x, (x + 3)^{2} = 8 (y - 1)^{3}

What are the solutions to the equation 0=x^2-0.3x-0.1 ?
The solutions to the equation 0=x^2-0.3x-0.1 are x= 1/2 ,x=-1/5
Find the zeros of 0=x^2-0.3x-0.1
The zeros of 0=x^2-0.3x-0.1 are x= 1/2 ,x=-1/5