What are the solutions to the equation 3t^2=12+5t ?

The solutions to the equation 3t^2=12+5t are t=3,t=-4/3

Find the zeros of 3t^2=12+5t

The zeros of 3t^2=12+5t are t=3,t=-4/3

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3 t^{2} = 12 + 5 t

t = 3, t = - \frac{4}{3}

Decimal Notation

t = 3, t = - 1.33333 \dots

Solution steps

3 t^{2} = 12 + 5 t

Move

5 t

to the left side

3 t^{2} - 5 t = 12

Move

12

to the left side

3 t^{2} - 5 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 12) = 13

t_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 3}, t_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 3}

t = \frac{- ( - 5 ) + 13}{2 \cdot 3} : 3

t = \frac{- ( - 5 ) - 13}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

t = 3, t = - \frac{4}{3}

(x - 36)^{2} = 0

3 x^{2} - 80 x + 430 = 0

x^{2} + (x - 1)^{2} = (x + 1)^{2}

4 k^{2} - 7 k + 2 = k^{2}

2 x^{2} - 21 x + 27 = 0

What are the solutions to the equation 3t^2=12+5t ?
The solutions to the equation 3t^2=12+5t are t=3,t=-4/3
Find the zeros of 3t^2=12+5t
The zeros of 3t^2=12+5t are t=3,t=-4/3