What are the solutions to the equation m^2-3m-11=-6m ?

The solutions to the equation m^2-3m-11=-6m are m=(-3+sqrt(53))/2 ,m=(-3-sqrt(53))/2

Find the zeros of m^2-3m-11=-6m

The zeros of m^2-3m-11=-6m are m=(-3+sqrt(53))/2 ,m=(-3-sqrt(53))/2

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m^{2} - 3 m - 11 = - 6 m

m = \frac{- 3 + 53}{2}, m = \frac{- 3 - 53}{2}

Decimal Notation

m = 2.14005 \dots, m = - 5.14005 \dots

Solution steps

m^{2} - 3 m - 11 = - 6 m

Move

6 m

to the left side

m^{2} + 3 m - 11 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 11) = 53

m_{1, 2} = \frac{- 3 \pm 53}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 3 + 53}{2 \cdot 1}, m_{2} = \frac{- 3 - 53}{2 \cdot 1}

m = \frac{- 3 + 53}{2 \cdot 1} : \frac{- 3 + 53}{2}

m = \frac{- 3 - 53}{2 \cdot 1} : \frac{- 3 - 53}{2}

The solutions to the quadratic equation are:

m = \frac{- 3 + 53}{2}, m = \frac{- 3 - 53}{2}

5 (x^{2} + \frac{2}{5}) = 2 (2 x^{2} + 1)

m^{2} - 30 m - 675 = 0

2 x (1 - x) = 5 x

2 x^{2} + 3 x - 90 = 0

x, y = (x - 1)^{2}

What are the solutions to the equation m^2-3m-11=-6m ?
The solutions to the equation m^2-3m-11=-6m are m=(-3+sqrt(53))/2 ,m=(-3-sqrt(53))/2
Find the zeros of m^2-3m-11=-6m
The zeros of m^2-3m-11=-6m are m=(-3+sqrt(53))/2 ,m=(-3-sqrt(53))/2