What are the solutions to the equation 3x^2+10x-4=-x ?

The solutions to the equation 3x^2+10x-4=-x are x= 1/3 ,x=-4

Find the zeros of 3x^2+10x-4=-x

The zeros of 3x^2+10x-4=-x are x= 1/3 ,x=-4

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3 x^{2} + 10 x - 4 = - x

x = \frac{1}{3}, x = - 4

Decimal Notation

x = 0.33333 \dots, x = - 4

Solution steps

3 x^{2} + 10 x - 4 = - x

Move

x

to the left side

3 x^{2} + 11 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 (- 4) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 3}, x_{2} = \frac{- 11 - 13}{2 \cdot 3}

x = \frac{- 11 + 13}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 11 - 13}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 4

(x - 8) (2 x + 10) = (x + 2) (x - 1)

k^{2} - 9 k + 11 = 0

686 = - 0.25 q^{2} + 750

x, x^{2} + y^{2} + z^{2} = 49

x, z x^{2} - x + 5 - 3 z = 0

What are the solutions to the equation 3x^2+10x-4=-x ?
The solutions to the equation 3x^2+10x-4=-x are x= 1/3 ,x=-4
Find the zeros of 3x^2+10x-4=-x
The zeros of 3x^2+10x-4=-x are x= 1/3 ,x=-4