What are the solutions to the equation 3x^2+35=7x^2-4x ?

The solutions to the equation 3x^2+35=7x^2-4x are x=-5/2 ,x= 7/2

Find the zeros of 3x^2+35=7x^2-4x

The zeros of 3x^2+35=7x^2-4x are x=-5/2 ,x= 7/2

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3 x^{2} + 35 = 7 x^{2} - 4 x

x = - \frac{5}{2}, x = \frac{7}{2}

Decimal Notation

x = - 2.5, x = 3.5

Solution steps

3 x^{2} + 35 = 7 x^{2} - 4 x

Move

4 x

to the left side

3 x^{2} + 35 + 4 x = 7 x^{2}

Move

7 x^{2}

to the left side

- 4 x^{2} + 4 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) \cdot 35}{2 ( - 4 )}

4^{2} - 4 (- 4) \cdot 35 = 24

x_{1, 2} = \frac{- 4 \pm 24}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 4 + 24}{2 ( - 4 )}, x_{2} = \frac{- 4 - 24}{2 ( - 4 )}

x = \frac{- 4 + 24}{2 ( - 4 )} : - \frac{5}{2}

x = \frac{- 4 - 24}{2 ( - 4 )} : \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = \frac{7}{2}

\frac{1}{2} x^{2} + x = 5

- m^{2} - m + 2 = 0

x^{2} + \frac{5}{3} x - \frac{2}{3} = 0

121 x^{2} + 64 = 0

- 0.25 q^{2} + 1500 = 83 q + 468

What are the solutions to the equation 3x^2+35=7x^2-4x ?
The solutions to the equation 3x^2+35=7x^2-4x are x=-5/2 ,x= 7/2
Find the zeros of 3x^2+35=7x^2-4x
The zeros of 3x^2+35=7x^2-4x are x=-5/2 ,x= 7/2