What are the solutions to the equation 4k^2-4k=0 ?

The solutions to the equation 4k^2-4k=0 are k=1,k=0

Find the zeros of 4k^2-4k=0

The zeros of 4k^2-4k=0 are k=1,k=0

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4 k^{2} - 4 k = 0

k = 1, k = 0

Solution steps

4 k^{2} - 4 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 0 = 4

k_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 4}, k_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 4}

k = \frac{- ( - 4 ) + 4}{2 \cdot 4} : 1

k = \frac{- ( - 4 ) - 4}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

k = 1, k = 0

x^{2} - 7 x = 4

x, y^{3} = 1 - x^{2}

9 w^{2} + 17 w + 12 = 3 w^{2}

x^{2} = 4 x - 7

ln (2) x^{2} + ln (8) = 4

What are the solutions to the equation 4k^2-4k=0 ?
The solutions to the equation 4k^2-4k=0 are k=1,k=0
Find the zeros of 4k^2-4k=0
The zeros of 4k^2-4k=0 are k=1,k=0