What are the solutions to the equation y^2+16y+13=0 ?

The solutions to the equation y^2+16y+13=0 are y=-8+sqrt(51),y=-8-sqrt(51)

Find the zeros of y^2+16y+13=0

The zeros of y^2+16y+13=0 are y=-8+sqrt(51),y=-8-sqrt(51)

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y^{2} + 16 y + 13 = 0

y = - 8 + 51, y = - 8 - 51

Decimal Notation

y = - 0.85857 \dots, y = - 15.14142 \dots

Solution steps

y^{2} + 16 y + 13 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 13 = 251

y_{1, 2} = \frac{- 16 \pm 2 51}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 16 + 2 51}{2 \cdot 1}, y_{2} = \frac{- 16 - 2 51}{2 \cdot 1}

y = \frac{- 16 + 2 51}{2 \cdot 1} : - 8 + 51

y = \frac{- 16 - 2 51}{2 \cdot 1} : - 8 - 51

The solutions to the quadratic equation are:

y = - 8 + 51, y = - 8 - 51

6 x^{2} + 3 x = 1 + 2 x

3 x^{2} - 20 x - 13 = - 6

- 25 + 100 x^{2} = 0

0 = x^{2} - 30 x - 75

r^{2} + 4 r - 2 = 0

What are the solutions to the equation y^2+16y+13=0 ?
The solutions to the equation y^2+16y+13=0 are y=-8+sqrt(51),y=-8-sqrt(51)
Find the zeros of y^2+16y+13=0
The zeros of y^2+16y+13=0 are y=-8+sqrt(51),y=-8-sqrt(51)