What are the solutions to the equation 15w^2-w-20=3w^2 ?

The solutions to the equation 15w^2-w-20=3w^2 are w= 4/3 ,w=-5/4

Find the zeros of 15w^2-w-20=3w^2

The zeros of 15w^2-w-20=3w^2 are w= 4/3 ,w=-5/4

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15 w^{2} - w - 20 = 3 w^{2}

w = \frac{4}{3}, w = - \frac{5}{4}

Decimal Notation

w = 1.33333 \dots, w = - 1.25

Solution steps

15 w^{2} - w - 20 = 3 w^{2}

Move

3 w^{2}

to the left side

12 w^{2} - w - 20 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 12 ( - 20 )}{2 \cdot 12}

(- 1)^{2} - 4 \cdot 12 (- 20) = 31

w_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 12}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 12}, w_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 12}

w = \frac{- ( - 1 ) + 31}{2 \cdot 12} : \frac{4}{3}

w = \frac{- ( - 1 ) - 31}{2 \cdot 12} : - \frac{5}{4}

The solutions to the quadratic equation are:

w = \frac{4}{3}, w = - \frac{5}{4}

x^{2} - \frac{11}{4} x - \frac{3}{4} = 0

x^{2} - 7 x = 10 x - 70

8 x^{2} + 9 x + 2 = 0

x = 2 x^{2} - 5 x + 3

4 y^{2} + 17 y + 17 = 1

What are the solutions to the equation 15w^2-w-20=3w^2 ?
The solutions to the equation 15w^2-w-20=3w^2 are w= 4/3 ,w=-5/4
Find the zeros of 15w^2-w-20=3w^2
The zeros of 15w^2-w-20=3w^2 are w= 4/3 ,w=-5/4