What are the solutions to the equation 2x^2-12x=-18 ?

The solutions to the equation 2x^2-12x=-18 are x=3

Find the zeros of 2x^2-12x=-18

The zeros of 2x^2-12x=-18 are x=3

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2 x^{2} - 12 x = - 18

x = 3

Solution steps

2 x^{2} - 12 x = - 18

Move

18

to the left side

2 x^{2} - 12 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 18}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 18 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 2}

x = \frac{- ( - 12 )}{2 \cdot 2}

\frac{- ( - 12 )}{2 \cdot 2} = 3

x = 3

The solution to the quadratic equation is:

x = 3

(x + 1)^{2} = x - 1

12 x^{2} - 30 x + 10 = 0

x^{2} + 7 = 8 x

3 x^{2} + 1 = - 25 x - 7

x, x^{2} + x y + y^{2} = 9

What are the solutions to the equation 2x^2-12x=-18 ?
The solutions to the equation 2x^2-12x=-18 are x=3
Find the zeros of 2x^2-12x=-18
The zeros of 2x^2-12x=-18 are x=3