What are the solutions to the equation factor 2x^2-4x-6=0 ?

The solutions to the equation factor 2x^2-4x-6=0 are x=-1,x=3

Find the zeros of factor 2x^2-4x-6=0

The zeros of factor 2x^2-4x-6=0 are x=-1,x=3

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2 x^{2} - 4 x - 6 = 0

x = - 1, x = 3

Solution steps

2 x^{2} - 4 x - 6 = 0

Factor

2 x^{2} - 4 x - 6 : 2 (x + 1) (x - 3)

2 (x + 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 1, x = 3

8 x^{2} - 20 x + 12 = 4

x, x^{2} + y^{3} = 2 x^{2} y

\frac{3 y ^{2}}{2} - 2 y = 2

62 x^{2} + 60 x - 30 = 6770

y, x^{2} + (y - x)^{2} = 1

What are the solutions to the equation factor 2x^2-4x-6=0 ?
The solutions to the equation factor 2x^2-4x-6=0 are x=-1,x=3
Find the zeros of factor 2x^2-4x-6=0
The zeros of factor 2x^2-4x-6=0 are x=-1,x=3