What are the solutions to the equation 25k^2+20k+3=-1 ?

The solutions to the equation 25k^2+20k+3=-1 are k=-2/5

Find the zeros of 25k^2+20k+3=-1

The zeros of 25k^2+20k+3=-1 are k=-2/5

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25 k^{2} + 20 k + 3 = - 1

k = - \frac{2}{5}

Decimal Notation

k = - 0.4

Solution steps

25 k^{2} + 20 k + 3 = - 1

Move

1

to the left side

25 k^{2} + 20 k + 4 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

2 0^{2} - 4 \cdot 25 \cdot 4 = 0

k_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 25}

k = \frac{- 20}{2 \cdot 25}

\frac{- 20}{2 \cdot 25} = - \frac{2}{5}

k = - \frac{2}{5}

The solution to the quadratic equation is:

k = - \frac{2}{5}

x, 2 x^{2} y - 2 x y = 0

y, x^{3} + x y^{2} - 2 y^{2} = 0

A x^{2} + 2 x + 3 = x^{2} - B x + C

x^{2} + 10 x + 5 = 30

y, x^{3} + y^{2} = 2 x y^{2}

What are the solutions to the equation 25k^2+20k+3=-1 ?
The solutions to the equation 25k^2+20k+3=-1 are k=-2/5
Find the zeros of 25k^2+20k+3=-1
The zeros of 25k^2+20k+3=-1 are k=-2/5