3x-8<= 23\lor-4x+26>= 6

Solution

3 x - 8 \leq 23 or - 4 x + 26 \geq 6

x \leq \frac{31}{3}

Interval Notation

(- \infty, \frac{31}{3}]

Decimal Notation

x \leq 10.33333 \dots

Solution steps

3 x - 8 \leq 23 or - 4 x + 26 \geq 6

3 x - 8 \leq 23 : x \leq \frac{31}{3}

- 4 x + 26 \geq 6 : x \leq 5

Combine the intervals

x \leq \frac{31}{3} or x \leq 5

Merge Overlapping Intervals

x \leq \frac{31}{3}

3 x + 2 (4 + 6 x) = 113

4 w^{2} + 20 w = - 25

49 x^{2} - 1 = 0

2 = (x - 2)^{2}

(1 - 4 i) (- 4 + 2 i)

What is 3x-8<= 23\lor-4x+26>= 6 ?
The solution to 3x-8<= 23\lor-4x+26>= 6 is x<= 31/3