What are the solutions to the equation 2w^2-5w-9=-1 ?

The solutions to the equation 2w^2-5w-9=-1 are w=(5+sqrt(89))/4 ,w=(5-sqrt(89))/4

Find the zeros of 2w^2-5w-9=-1

The zeros of 2w^2-5w-9=-1 are w=(5+sqrt(89))/4 ,w=(5-sqrt(89))/4

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2 w^{2} - 5 w - 9 = - 1

w = \frac{5 + 89}{4}, w = \frac{5 - 89}{4}

Decimal Notation

w = 3.60849 \dots, w = - 1.10849 \dots

Solution steps

2 w^{2} - 5 w - 9 = - 1

Move

1

to the left side

2 w^{2} - 5 w - 8 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 8) = 89

w_{1, 2} = \frac{- ( - 5 ) \pm 89}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 89}{2 \cdot 2}, w_{2} = \frac{- ( - 5 ) - 89}{2 \cdot 2}

w = \frac{- ( - 5 ) + 89}{2 \cdot 2} : \frac{5 + 89}{4}

w = \frac{- ( - 5 ) - 89}{2 \cdot 2} : \frac{5 - 89}{4}

The solutions to the quadratic equation are:

w = \frac{5 + 89}{4}, w = \frac{5 - 89}{4}

x^{2} + 9 x + 15 = - 5

5 x + 3 = - 2 x^{2}

2 x^{2} + 7 x + 52 = 0

m x^{2} + (2 m - 2) x + m = 0

x^{2} + (\frac{20 - 4 x}{3})^{2} = 25

What are the solutions to the equation 2w^2-5w-9=-1 ?
The solutions to the equation 2w^2-5w-9=-1 are w=(5+sqrt(89))/4 ,w=(5-sqrt(89))/4
Find the zeros of 2w^2-5w-9=-1
The zeros of 2w^2-5w-9=-1 are w=(5+sqrt(89))/4 ,w=(5-sqrt(89))/4