What are the solutions to the equation -x^2+6x=-1 ?

The solutions to the equation -x^2+6x=-1 are x=3-sqrt(10),x=3+sqrt(10)

Find the zeros of -x^2+6x=-1

The zeros of -x^2+6x=-1 are x=3-sqrt(10),x=3+sqrt(10)

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- x^{2} + 6 x = - 1

x = 3 - 10, x = 3 + 10

Decimal Notation

x = - 0.16227 \dots, x = 6.16227 \dots

Solution steps

- x^{2} + 6 x = - 1

Move

1

to the left side

- x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 1 = 210

x_{1, 2} = \frac{- 6 \pm 2 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 10}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 10}{2 ( - 1 )}

x = \frac{- 6 + 2 10}{2 ( - 1 )} : 3 - 10

x = \frac{- 6 - 2 10}{2 ( - 1 )} : 3 + 10

The solutions to the quadratic equation are:

x = 3 - 10, x = 3 + 10

9^{2} + x^{2} = 1 8^{2}

x^{2} + 55 = - 16 x - 5

2 x^{2} + 4 = 5 x + 2

x, x^{2} + y^{2} + z^{2} - 2 x - 4 y + 8 z + 17 = 0

y, x^{2} y^{2} + x y = 2

What are the solutions to the equation -x^2+6x=-1 ?
The solutions to the equation -x^2+6x=-1 are x=3-sqrt(10),x=3+sqrt(10)
Find the zeros of -x^2+6x=-1
The zeros of -x^2+6x=-1 are x=3-sqrt(10),x=3+sqrt(10)