What are the solutions to the equation solvefor x,-x^2+y^2+z^2=1 ?

The solutions to the equation solvefor x,-x^2+y^2+z^2=1 are x=sqrt(-1+y^2+z^2),x=-sqrt(-1+y^2+z^2)

Find the zeros of solvefor x,-x^2+y^2+z^2=1

The zeros of solvefor x,-x^2+y^2+z^2=1 are x=sqrt(-1+y^2+z^2),x=-sqrt(-1+y^2+z^2)

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solve for

x, - x^{2} + y^{2} + z^{2} = 1

x = - 1 + y^{2} + z^{2}, x = - - 1 + y^{2} + z^{2}

Solution steps

- x^{2} + y^{2} + z^{2} = 1

Move

y^{2}

to the right side

- x^{2} + z^{2} = 1 - y^{2}

Move

z^{2}

to the right side

- x^{2} = 1 - y^{2} - z^{2}

Divide both sides by

- 1

x^{2} = - 1 + y^{2} + z^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1 + y^{2} + z^{2}, x = - - 1 + y^{2} + z^{2}

8 x^{2} - 5 x + 87 = 7 x^{2} + 5 x

- 4 x^{2} + 17 x - 4 = 3 x + 2

4 x + (x + 2)^{2} = 3 x (x + 2)

x, x^{2} + y^{2} + z^{2} - 6 x + 2 y - 4 z + 19 = 0

9 x^{2} + 14 x + 16 = 0

What are the solutions to the equation solvefor x,-x^2+y^2+z^2=1 ?
The solutions to the equation solvefor x,-x^2+y^2+z^2=1 are x=sqrt(-1+y^2+z^2),x=-sqrt(-1+y^2+z^2)
Find the zeros of solvefor x,-x^2+y^2+z^2=1
The zeros of solvefor x,-x^2+y^2+z^2=1 are x=sqrt(-1+y^2+z^2),x=-sqrt(-1+y^2+z^2)