What are the solutions to the equation 3600=x^2-160x+10000 ?

The solutions to the equation 3600=x^2-160x+10000 are x=80

Find the zeros of 3600=x^2-160x+10000

The zeros of 3600=x^2-160x+10000 are x=80

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3600 = x^{2} - 160 x + 10000

x = 80

Solution steps

3600 = x^{2} - 160 x + 10000

Switch sides

x^{2} - 160 x + 10000 = 3600

Move

3600

to the left side

x^{2} - 160 x + 6400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 160 ) \pm ( - 160 ) ^{2} - 4 \cdot 1 \cdot 6400}{2 \cdot 1}

(- 160)^{2} - 4 \cdot 1 \cdot 6400 = 0

x_{1, 2} = \frac{- ( - 160 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 160 )}{2 \cdot 1}

\frac{- ( - 160 )}{2 \cdot 1} = 80

x = 80

The solution to the quadratic equation is:

x = 80

x, \frac{x ^{2}}{3} + 3 y^{2} = 0

8 - (x - 1) (3 - x) = 4 (x - 1)

(x + 2)^{2} = 4 (2 x + 3)

2 r^{2} + 7 r + 5 = 0

- 5 x^{2} - 2 x + 3 = 0

What are the solutions to the equation 3600=x^2-160x+10000 ?
The solutions to the equation 3600=x^2-160x+10000 are x=80
Find the zeros of 3600=x^2-160x+10000
The zeros of 3600=x^2-160x+10000 are x=80