What are the solutions to the equation 3x^2+x+4=-9x+1 ?

The solutions to the equation 3x^2+x+4=-9x+1 are x=-1/3 ,x=-3

Find the zeros of 3x^2+x+4=-9x+1

The zeros of 3x^2+x+4=-9x+1 are x=-1/3 ,x=-3

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3 x^{2} + x + 4 = - 9 x + 1

x = - \frac{1}{3}, x = - 3

Decimal Notation

x = - 0.33333 \dots, x = - 3

Solution steps

3 x^{2} + x + 4 = - 9 x + 1

Move

1

to the left side

3 x^{2} + x + 3 = - 9 x

Move

9 x

to the left side

3 x^{2} + 10 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 3 = 8

x_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 8}{2 \cdot 3}, x_{2} = \frac{- 10 - 8}{2 \cdot 3}

x = \frac{- 10 + 8}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 10 - 8}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 3

x, x^{2} + (1 - y)^{2} + 5 = 0

x, 7 x^{2} + 7 y^{2} - 2 x y - 6 x - 6 y = 9

- \frac{1}{2} x^{2} + 4 = x

3 - 14 x - 5 x^{2} = 0

z^{2} - 3 z - 4 = 0

What are the solutions to the equation 3x^2+x+4=-9x+1 ?
The solutions to the equation 3x^2+x+4=-9x+1 are x=-1/3 ,x=-3
Find the zeros of 3x^2+x+4=-9x+1
The zeros of 3x^2+x+4=-9x+1 are x=-1/3 ,x=-3