What are the solutions to the equation 40x^2+33x-18=0 ?

The solutions to the equation 40x^2+33x-18=0 are x= 3/8 ,x=-6/5

Find the zeros of 40x^2+33x-18=0

The zeros of 40x^2+33x-18=0 are x= 3/8 ,x=-6/5

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40 x^{2} + 33 x - 18 = 0

x = \frac{3}{8}, x = - \frac{6}{5}

Decimal Notation

x = 0.375, x = - 1.2

Solution steps

40 x^{2} + 33 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 \cdot 40 ( - 18 )}{2 \cdot 40}

3 3^{2} - 4 \cdot 40 (- 18) = 63

x_{1, 2} = \frac{- 33 \pm 63}{2 \cdot 40}

Separate the solutions

x_{1} = \frac{- 33 + 63}{2 \cdot 40}, x_{2} = \frac{- 33 - 63}{2 \cdot 40}

x = \frac{- 33 + 63}{2 \cdot 40} : \frac{3}{8}

x = \frac{- 33 - 63}{2 \cdot 40} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{3}{8}, x = - \frac{6}{5}

- 3 x^{2} - 5 = - x

- 8 x^{2} + 26 x - 15 = 0

x (x - 2) = 2 x - 2

(x - 2)^{2} - 6 = - (x + 2) (x + 1)

x^{2} + 13 x - 420 = 0

What are the solutions to the equation 40x^2+33x-18=0 ?
The solutions to the equation 40x^2+33x-18=0 are x= 3/8 ,x=-6/5
Find the zeros of 40x^2+33x-18=0
The zeros of 40x^2+33x-18=0 are x= 3/8 ,x=-6/5