What are the solutions to the equation 2b^2+11b+13=0 ?

The solutions to the equation 2b^2+11b+13=0 are b=(-11+sqrt(17))/4 ,b=(-11-sqrt(17))/4

Find the zeros of 2b^2+11b+13=0

The zeros of 2b^2+11b+13=0 are b=(-11+sqrt(17))/4 ,b=(-11-sqrt(17))/4

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2 b^{2} + 11 b + 13 = 0

b = \frac{- 11 + 17}{4}, b = \frac{- 11 - 17}{4}

Decimal Notation

b = - 1.71922 \dots, b = - 3.78077 \dots

Solution steps

2 b^{2} + 11 b + 13 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 13}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 13 = 17

b_{1, 2} = \frac{- 11 \pm 17}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- 11 + 17}{2 \cdot 2}, b_{2} = \frac{- 11 - 17}{2 \cdot 2}

b = \frac{- 11 + 17}{2 \cdot 2} : \frac{- 11 + 17}{4}

b = \frac{- 11 - 17}{2 \cdot 2} : \frac{- 11 - 17}{4}

The solutions to the quadratic equation are:

b = \frac{- 11 + 17}{4}, b = \frac{- 11 - 17}{4}

a, (a - b)^{2} = 64

x, x^{2} + y^{2} - 4 x - 10 y + 29 = 0

5 n^{2} - 3 n = 2

3 x^{2} + 7 x + 9 = 0

x^{2} + 20 x - 44 = 0

What are the solutions to the equation 2b^2+11b+13=0 ?
The solutions to the equation 2b^2+11b+13=0 are b=(-11+sqrt(17))/4 ,b=(-11-sqrt(17))/4
Find the zeros of 2b^2+11b+13=0
The zeros of 2b^2+11b+13=0 are b=(-11+sqrt(17))/4 ,b=(-11-sqrt(17))/4