What are the solutions to the equation 5a^2-7a+3=2 ?

The solutions to the equation 5a^2-7a+3=2 are a=(7+sqrt(29))/(10),a=(7-sqrt(29))/(10)

Find the zeros of 5a^2-7a+3=2

The zeros of 5a^2-7a+3=2 are a=(7+sqrt(29))/(10),a=(7-sqrt(29))/(10)

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5 a^{2} - 7 a + 3 = 2

a = \frac{7 + 29}{10}, a = \frac{7 - 29}{10}

Decimal Notation

a = 1.23851 \dots, a = 0.16148 \dots

Solution steps

5 a^{2} - 7 a + 3 = 2

Move

2

to the left side

5 a^{2} - 7 a + 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 \cdot 1 = 29

a_{1, 2} = \frac{- ( - 7 ) \pm 29}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 29}{2 \cdot 5}, a_{2} = \frac{- ( - 7 ) - 29}{2 \cdot 5}

a = \frac{- ( - 7 ) + 29}{2 \cdot 5} : \frac{7 + 29}{10}

a = \frac{- ( - 7 ) - 29}{2 \cdot 5} : \frac{7 - 29}{10}

The solutions to the quadratic equation are:

a = \frac{7 + 29}{10}, a = \frac{7 - 29}{10}

x^{2} + 3 = 5

(7 y + 15)^{2} = 99

3 r^{2} + 9 r - 7 = - 6

90 - 76 x + 12 x^{2} = 0

2 a^{2} + 3 a - 2 = 0

What are the solutions to the equation 5a^2-7a+3=2 ?
The solutions to the equation 5a^2-7a+3=2 are a=(7+sqrt(29))/(10),a=(7-sqrt(29))/(10)
Find the zeros of 5a^2-7a+3=2
The zeros of 5a^2-7a+3=2 are a=(7+sqrt(29))/(10),a=(7-sqrt(29))/(10)