What are the solutions to the equation x^2+x(x-6)=0 ?

The solutions to the equation x^2+x(x-6)=0 are x=3,x=0

Find the zeros of x^2+x(x-6)=0

The zeros of x^2+x(x-6)=0 are x=3,x=0

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x^{2} + x (x - 6) = 0

x = 3, x = 0

Solution steps

x^{2} + x (x - 6) = 0

Expand

x^{2} + x (x - 6) : 2 x^{2} - 6 x

2 x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 2}

x = \frac{- ( - 6 ) + 6}{2 \cdot 2} : 3

x = \frac{- ( - 6 ) - 6}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

x, 3 x^{2} + 4 x - 4 = 0

4 y^{2} - 4 y + 5

x, 2 x^{2} + 2 y^{2} + 4 x + 2 y + 5 = 0

(x + 2) (x - 3) = 2

15 = 2 x^{2} - 3 x + 1

What are the solutions to the equation x^2+x(x-6)=0 ?
The solutions to the equation x^2+x(x-6)=0 are x=3,x=0
Find the zeros of x^2+x(x-6)=0
The zeros of x^2+x(x-6)=0 are x=3,x=0