What are the solutions to the equation -3x^2+7x=-2x-8 ?

The solutions to the equation -3x^2+7x=-2x-8 are x=-(-9+sqrt(177))/6 ,x=(9+sqrt(177))/6

Find the zeros of -3x^2+7x=-2x-8

The zeros of -3x^2+7x=-2x-8 are x=-(-9+sqrt(177))/6 ,x=(9+sqrt(177))/6

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- 3 x^{2} + 7 x = - 2 x - 8

x = - \frac{- 9 + 177}{6}, x = \frac{9 + 177}{6}

Decimal Notation

x = - 0.71735 \dots, x = 3.71735 \dots

Solution steps

- 3 x^{2} + 7 x = - 2 x - 8

Move

8

to the left side

- 3 x^{2} + 7 x + 8 = - 2 x

Move

2 x

to the left side

- 3 x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

9^{2} - 4 (- 3) \cdot 8 = 177

x_{1, 2} = \frac{- 9 \pm 177}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 9 + 177}{2 ( - 3 )}, x_{2} = \frac{- 9 - 177}{2 ( - 3 )}

x = \frac{- 9 + 177}{2 ( - 3 )} : - \frac{- 9 + 177}{6}

x = \frac{- 9 - 177}{2 ( - 3 )} : \frac{9 + 177}{6}

The solutions to the quadratic equation are:

x = - \frac{- 9 + 177}{6}, x = \frac{9 + 177}{6}

x + 1 = x^{2} - 1

- x^{2} - 2 x - 3 = - 2 x^{2}

x, 3 x^{2} + 3 y^{2} - 6 x + 12 y + 60 = 0

4 d^{2} + d + 1 = - 3 d

(x - 16)^{2} = 256

What are the solutions to the equation -3x^2+7x=-2x-8 ?
The solutions to the equation -3x^2+7x=-2x-8 are x=-(-9+sqrt(177))/6 ,x=(9+sqrt(177))/6
Find the zeros of -3x^2+7x=-2x-8
The zeros of -3x^2+7x=-2x-8 are x=-(-9+sqrt(177))/6 ,x=(9+sqrt(177))/6