What are the solutions to the equation n^2-7n+3=-2n ?

The solutions to the equation n^2-7n+3=-2n are n=(5+sqrt(13))/2 ,n=(5-sqrt(13))/2

Find the zeros of n^2-7n+3=-2n

The zeros of n^2-7n+3=-2n are n=(5+sqrt(13))/2 ,n=(5-sqrt(13))/2

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n^{2} - 7 n + 3 = - 2 n

n = \frac{5 + 13}{2}, n = \frac{5 - 13}{2}

Decimal Notation

n = 4.30277 \dots, n = 0.69722 \dots

Solution steps

n^{2} - 7 n + 3 = - 2 n

Move

2 n

to the left side

n^{2} - 5 n + 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 3 = 13

n_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, n_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

n = \frac{- ( - 5 ) + 13}{2 \cdot 1} : \frac{5 + 13}{2}

n = \frac{- ( - 5 ) - 13}{2 \cdot 1} : \frac{5 - 13}{2}

The solutions to the quadratic equation are:

n = \frac{5 + 13}{2}, n = \frac{5 - 13}{2}

y^{2} + 11 y + 24 = 0

80 t - 16 t^{2} = 0

5 x^{2} - 19 x + 3 = 2 x - 1

3 x^{2} + 12 = 22 x + 5

5 x^{2} - 10 x = 240

What are the solutions to the equation n^2-7n+3=-2n ?
The solutions to the equation n^2-7n+3=-2n are n=(5+sqrt(13))/2 ,n=(5-sqrt(13))/2
Find the zeros of n^2-7n+3=-2n
The zeros of n^2-7n+3=-2n are n=(5+sqrt(13))/2 ,n=(5-sqrt(13))/2