What are the solutions to the equation 5x^2-17x+13=0 ?

The solutions to the equation 5x^2-17x+13=0 are x=(17+sqrt(29))/(10),x=(17-sqrt(29))/(10)

Find the zeros of 5x^2-17x+13=0

The zeros of 5x^2-17x+13=0 are x=(17+sqrt(29))/(10),x=(17-sqrt(29))/(10)

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5 x^{2} - 17 x + 13 = 0

x = \frac{17 + 29}{10}, x = \frac{17 - 29}{10}

Decimal Notation

x = 2.23851 \dots, x = 1.16148 \dots

Solution steps

5 x^{2} - 17 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 \cdot 13}{2 \cdot 5}

(- 17)^{2} - 4 \cdot 5 \cdot 13 = 29

x_{1, 2} = \frac{- ( - 17 ) \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 29}{2 \cdot 5}, x_{2} = \frac{- ( - 17 ) - 29}{2 \cdot 5}

x = \frac{- ( - 17 ) + 29}{2 \cdot 5} : \frac{17 + 29}{10}

x = \frac{- ( - 17 ) - 29}{2 \cdot 5} : \frac{17 - 29}{10}

The solutions to the quadratic equation are:

x = \frac{17 + 29}{10}, x = \frac{17 - 29}{10}

x, 2 x^{2} - 5 x y + 2 y^{2} = 0

x^{2} - 2 x - 52 = 3 x - 2

(x - 5) (x - 3) = 15

y, y^{2} = x^{3} + x + 17

x, f (x + 3) = x^{2} - 1

What are the solutions to the equation 5x^2-17x+13=0 ?
The solutions to the equation 5x^2-17x+13=0 are x=(17+sqrt(29))/(10),x=(17-sqrt(29))/(10)
Find the zeros of 5x^2-17x+13=0
The zeros of 5x^2-17x+13=0 are x=(17+sqrt(29))/(10),x=(17-sqrt(29))/(10)