What are the solutions to the equation -x^2+4x= 3/2 x ?

The solutions to the equation -x^2+4x= 3/2 x are x=0,x= 5/2

Find the zeros of -x^2+4x= 3/2 x

The zeros of -x^2+4x= 3/2 x are x=0,x= 5/2

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- x^{2} + 4 x = \frac{3}{2} x

x = 0, x = \frac{5}{2}

Decimal Notation

x = 0, x = 2.5

Solution steps

- x^{2} + 4 x = \frac{3}{2} x

Multiply both sides by

2

- 2 x^{2} + 8 x = 3 x

Move

3 x

to the left side

- 2 x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 ( - 2 )}, x_{2} = \frac{- 5 - 5}{2 ( - 2 )}

x = \frac{- 5 + 5}{2 ( - 2 )} : 0

x = \frac{- 5 - 5}{2 ( - 2 )} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{5}{2}

- 10 q^{2} - 3 q - 9 = - 2 q

3 a^{2} - 7 a - 2 = 0

x^{2} + 6 x + 6 + 8 = 0

- x^{2} + 4 x + 2 = x + 2

14 x^{2} + 17 x + 6 = 0

What are the solutions to the equation -x^2+4x= 3/2 x ?
The solutions to the equation -x^2+4x= 3/2 x are x=0,x= 5/2
Find the zeros of -x^2+4x= 3/2 x
The zeros of -x^2+4x= 3/2 x are x=0,x= 5/2