What are the solutions to the equation 5x^2-12x+7=0 ?

The solutions to the equation 5x^2-12x+7=0 are x= 7/5 ,x=1

Find the zeros of 5x^2-12x+7=0

The zeros of 5x^2-12x+7=0 are x= 7/5 ,x=1

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5 x^{2} - 12 x + 7 = 0

x = \frac{7}{5}, x = 1

Decimal Notation

x = 1.4, x = 1

Solution steps

5 x^{2} - 12 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 \cdot 7 = 2

x_{1, 2} = \frac{- ( - 12 ) \pm 2}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 2}{2 \cdot 5}

x = \frac{- ( - 12 ) + 2}{2 \cdot 5} : \frac{7}{5}

x = \frac{- ( - 12 ) - 2}{2 \cdot 5} : 1

The solutions to the quadratic equation are:

x = \frac{7}{5}, x = 1

26 x^{2} - 13 x

2 x^{2} - 30 = 70

16 - 12 x^{2} = 0

12 x^{2} + 15 x - 21 = 0

t, 15 m = \frac{( \frac{10 m}{s ^{2}} ) \cdot t ^{2}}{2}

What are the solutions to the equation 5x^2-12x+7=0 ?
The solutions to the equation 5x^2-12x+7=0 are x= 7/5 ,x=1
Find the zeros of 5x^2-12x+7=0
The zeros of 5x^2-12x+7=0 are x= 7/5 ,x=1