What are the solutions to the equation factor 9x^2-42x+45=0 ?

The solutions to the equation factor 9x^2-42x+45=0 are x= 5/3 ,x=3

Find the zeros of factor 9x^2-42x+45=0

The zeros of factor 9x^2-42x+45=0 are x= 5/3 ,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 42 x + 45 = 0

x = \frac{5}{3}, x = 3

Decimal Notation

x = 1.66666 \dots, x = 3

Solution steps

9 x^{2} - 42 x + 45 = 0

Factor

9 x^{2} - 42 x + 45 : 3 (3 x - 5) (x - 3)

3 (3 x - 5) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 5 = 0 or x - 3 = 0

Solve

3 x - 5 = 0 : x = \frac{5}{3}

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = 3

x^{2} + x - 48 = 0

z^{2} + 5 z - 3 = 0

5 x^{2} - 20 = 10 x

52 - x^{2} = - 4

What are the solutions to the equation factor 9x^2-42x+45=0 ?
The solutions to the equation factor 9x^2-42x+45=0 are x= 5/3 ,x=3
Find the zeros of factor 9x^2-42x+45=0
The zeros of factor 9x^2-42x+45=0 are x= 5/3 ,x=3