What are the solutions to the equation 20x^2+10x+5=11x+6 ?

The solutions to the equation 20x^2+10x+5=11x+6 are x= 1/4 ,x=-1/5

Find the zeros of 20x^2+10x+5=11x+6

The zeros of 20x^2+10x+5=11x+6 are x= 1/4 ,x=-1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

20 x^{2} + 10 x + 5 = 11 x + 6

x = \frac{1}{4}, x = - \frac{1}{5}

Decimal Notation

x = 0.25, x = - 0.2

Solution steps

20 x^{2} + 10 x + 5 = 11 x + 6

Move

6

to the left side

20 x^{2} + 10 x - 1 = 11 x

Move

11 x

to the left side

20 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 20 ( - 1 )}{2 \cdot 20}

(- 1)^{2} - 4 \cdot 20 (- 1) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 20}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 20}

x = \frac{- ( - 1 ) + 9}{2 \cdot 20} : \frac{1}{4}

x = \frac{- ( - 1 ) - 9}{2 \cdot 20} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{1}{5}

(3 + x) \frac{2}{5} + 6 (3 - x) \frac{2}{5} = 5 (9 - x^{2}) \frac{1}{5}

x^{2} - 10 = 71

x^{2} + 5 x - 22 = 6 x + 2

x, x^{2} + y^{2} = x^{2} y^{2}

x, 4 x^{2} + 4 y^{2} + 12 x - 24 y + 45 = 0

What are the solutions to the equation 20x^2+10x+5=11x+6 ?
The solutions to the equation 20x^2+10x+5=11x+6 are x= 1/4 ,x=-1/5
Find the zeros of 20x^2+10x+5=11x+6
The zeros of 20x^2+10x+5=11x+6 are x= 1/4 ,x=-1/5