What are the solutions to the equation 2(x-3)(x+10)=0 ?

The solutions to the equation 2(x-3)(x+10)=0 are x=3,x=-10

Find the zeros of 2(x-3)(x+10)=0

The zeros of 2(x-3)(x+10)=0 are x=3,x=-10

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2 (x - 3) (x + 10) = 0

x = 3, x = - 10

Solution steps

2 (x - 3) (x + 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 10 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 10 = 0 : x = - 10

The solutions to the quadratic equation are:

x = 3, x = - 10

4 x^{2} - 11 x + 6 = x^{2}

q^{2} - 9 q + 1 = 2

- 3 x^{2} + 7 x - 4 = 0

4 b^{2} - 7 b + 6 = 5

\frac{2 ( x ^{2} + 1 )}{5} - \frac{17 x + 16}{10} = x^{2}

What are the solutions to the equation 2(x-3)(x+10)=0 ?
The solutions to the equation 2(x-3)(x+10)=0 are x=3,x=-10
Find the zeros of 2(x-3)(x+10)=0
The zeros of 2(x-3)(x+10)=0 are x=3,x=-10