What are the solutions to the equation 120=5(t)^2 ?

The solutions to the equation 120=5(t)^2 are t=2sqrt(6),t=-2sqrt(6)

Find the zeros of 120=5(t)^2

The zeros of 120=5(t)^2 are t=2sqrt(6),t=-2sqrt(6)

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120 = 5 (t)^{2}

t = 26, t = - 26

Decimal Notation

t = 4.89897 \dots, t = - 4.89897 \dots

Solution steps

120 = 5 t^{2}

Switch sides

5 t^{2} = 120

Divide both sides by

5

t^{2} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 24, t = - 24

24 = 26

- 24 = - 26

t = 26, t = - 26

d^{2} + 6 d + 5 = 0

x^{2} + 16 x = 5

x^{2} - 7 = 57

a, 2 - j^{4} = (a + 3 jb)^{2}

0 = 2 x^{2} + x - 3

What are the solutions to the equation 120=5(t)^2 ?
The solutions to the equation 120=5(t)^2 are t=2sqrt(6),t=-2sqrt(6)
Find the zeros of 120=5(t)^2
The zeros of 120=5(t)^2 are t=2sqrt(6),t=-2sqrt(6)