What are the solutions to the equation -2z^2-5z-5=-5z^2 ?

The solutions to the equation -2z^2-5z-5=-5z^2 are z=(5+sqrt(85))/6 ,z=(5-sqrt(85))/6

Find the zeros of -2z^2-5z-5=-5z^2

The zeros of -2z^2-5z-5=-5z^2 are z=(5+sqrt(85))/6 ,z=(5-sqrt(85))/6

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- 2 z^{2} - 5 z - 5 = - 5 z^{2}

z = \frac{5 + 85}{6}, z = \frac{5 - 85}{6}

Decimal Notation

z = 2.36992 \dots, z = - 0.70325 \dots

Solution steps

- 2 z^{2} - 5 z - 5 = - 5 z^{2}

Move

5 z^{2}

to the left side

3 z^{2} - 5 z - 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 5) = 85

z_{1, 2} = \frac{- ( - 5 ) \pm 85}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- ( - 5 ) + 85}{2 \cdot 3}, z_{2} = \frac{- ( - 5 ) - 85}{2 \cdot 3}

z = \frac{- ( - 5 ) + 85}{2 \cdot 3} : \frac{5 + 85}{6}

z = \frac{- ( - 5 ) - 85}{2 \cdot 3} : \frac{5 - 85}{6}

The solutions to the quadratic equation are:

z = \frac{5 + 85}{6}, z = \frac{5 - 85}{6}

- 2 (- x + 5) 5 x + 2 = 27

y^{2} - 8 y - 9 = 0

(x - 4)^{2} - 3 = 0

6 x^{2} - 3 x - 3 = - 10 x

x^{2} + 2 a x = 0

What are the solutions to the equation -2z^2-5z-5=-5z^2 ?
The solutions to the equation -2z^2-5z-5=-5z^2 are z=(5+sqrt(85))/6 ,z=(5-sqrt(85))/6
Find the zeros of -2z^2-5z-5=-5z^2
The zeros of -2z^2-5z-5=-5z^2 are z=(5+sqrt(85))/6 ,z=(5-sqrt(85))/6