What are the solutions to the equation x^2-6x+25=0 ?

The solutions to the equation x^2-6x+25=0 are x=3+4i,x=3-4i

Find the zeros of x^2-6x+25=0

The zeros of x^2-6x+25=0 are x=3+4i,x=3-4i

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x^{2} - 6 x + 25 = 0

x = 3 + 4 i, x = 3 - 4 i

Solution steps

x^{2} - 6 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 25 : 8 i

x_{1, 2} = \frac{- ( - 6 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 8 i}{2 \cdot 1} : 3 + 4 i

x = \frac{- ( - 6 ) - 8 i}{2 \cdot 1} : 3 - 4 i

The solutions to the quadratic equation are:

x = 3 + 4 i, x = 3 - 4 i

(a b^{2} c^{2})^{\frac{3}{4}}

\frac{5}{2} \cdot \frac{3}{10}

3 x - 5 + x = 7

\frac{42}{( - 7 )}

6 - 9 i

What are the solutions to the equation x^2-6x+25=0 ?
The solutions to the equation x^2-6x+25=0 are x=3+4i,x=3-4i
Find the zeros of x^2-6x+25=0
The zeros of x^2-6x+25=0 are x=3+4i,x=3-4i