What are the solutions to the equation λ^2-2λ-3=0 ?

The solutions to the equation λ^2-2λ-3=0 are λ=3,λ=-1

Find the zeros of λ^2-2λ-3=0

The zeros of λ^2-2λ-3=0 are λ=3,λ=-1

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λ^{2} - 2 λ - 3 = 0

λ = 3, λ = - 1

Solution steps

λ^{2} - 2 λ - 3 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

λ_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, λ_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

λ = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

λ = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

λ = 3, λ = - 1

λ^{2} + aλ - 2 a^{2} = 0

(18 - x)^{2} + (5 - x)^{2} = 81

m^{2} + 3 = 51

x, f = {x^{2}}

x^{2} + 14 x = - 46

What are the solutions to the equation λ^2-2λ-3=0 ?
The solutions to the equation λ^2-2λ-3=0 are λ=3,λ=-1
Find the zeros of λ^2-2λ-3=0
The zeros of λ^2-2λ-3=0 are λ=3,λ=-1