What are the solutions to the equation y^2-y-14=2y ?

The solutions to the equation y^2-y-14=2y are y=(3+sqrt(65))/2 ,y=(3-sqrt(65))/2

Find the zeros of y^2-y-14=2y

The zeros of y^2-y-14=2y are y=(3+sqrt(65))/2 ,y=(3-sqrt(65))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - y - 14 = 2 y

y = \frac{3 + 65}{2}, y = \frac{3 - 65}{2}

Decimal Notation

y = 5.53112 \dots, y = - 2.53112 \dots

Solution steps

y^{2} - y - 14 = 2 y

Move

2 y

to the left side

y^{2} - 3 y - 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 14) = 65

y_{1, 2} = \frac{- ( - 3 ) \pm 65}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 65}{2 \cdot 1}, y_{2} = \frac{- ( - 3 ) - 65}{2 \cdot 1}

y = \frac{- ( - 3 ) + 65}{2 \cdot 1} : \frac{3 + 65}{2}

y = \frac{- ( - 3 ) - 65}{2 \cdot 1} : \frac{3 - 65}{2}

The solutions to the quadratic equation are:

y = \frac{3 + 65}{2}, y = \frac{3 - 65}{2}

\frac{1}{8} x^{2} + \frac{1}{4} x = 2

x^{2} - 17 x = - 10 x - 6

- 15 x^{2} = 0

(a x + 2) (b x + 7) = 15 x^{2} + c x + 14

x^{2} - (m + 1) x - 5 = 0

What are the solutions to the equation y^2-y-14=2y ?
The solutions to the equation y^2-y-14=2y are y=(3+sqrt(65))/2 ,y=(3-sqrt(65))/2
Find the zeros of y^2-y-14=2y
The zeros of y^2-y-14=2y are y=(3+sqrt(65))/2 ,y=(3-sqrt(65))/2