What are the solutions to the equation 0=-8x^2+560x ?

The solutions to the equation 0=-8x^2+560x are x=0,x=70

Find the zeros of 0=-8x^2+560x

The zeros of 0=-8x^2+560x are x=0,x=70

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0 = - 8 x^{2} + 560 x

x = 0, x = 70

Solution steps

0 = - 8 x^{2} + 560 x

Switch sides

- 8 x^{2} + 560 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 560 \pm 56 0 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

56 0^{2} - 4 (- 8) \cdot 0 = 560

x_{1, 2} = \frac{- 560 \pm 560}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 560 + 560}{2 ( - 8 )}, x_{2} = \frac{- 560 - 560}{2 ( - 8 )}

x = \frac{- 560 + 560}{2 ( - 8 )} : 0

x = \frac{- 560 - 560}{2 ( - 8 )} : 70

The solutions to the quadratic equation are:

x = 0, x = 70

2 x^{2} - 4 x = 6

6 - 3 x^{2} = 0

4 u^{2} = - 20 u - 25

x^{2} + 0 x + 16 = 0

x^{2} - 8 x - 7 = 0

What are the solutions to the equation 0=-8x^2+560x ?
The solutions to the equation 0=-8x^2+560x are x=0,x=70
Find the zeros of 0=-8x^2+560x
The zeros of 0=-8x^2+560x are x=0,x=70