What are the solutions to the equation 16x^2-24x-7=0 ?

The solutions to the equation 16x^2-24x-7=0 are x= 7/4 ,x=-1/4

Find the zeros of 16x^2-24x-7=0

The zeros of 16x^2-24x-7=0 are x= 7/4 ,x=-1/4

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16 x^{2} - 24 x - 7 = 0

x = \frac{7}{4}, x = - \frac{1}{4}

Decimal Notation

x = 1.75, x = - 0.25

Solution steps

16 x^{2} - 24 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 ( - 7 )}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 (- 7) = 32

x_{1, 2} = \frac{- ( - 24 ) \pm 32}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 32}{2 \cdot 16}, x_{2} = \frac{- ( - 24 ) - 32}{2 \cdot 16}

x = \frac{- ( - 24 ) + 32}{2 \cdot 16} : \frac{7}{4}

x = \frac{- ( - 24 ) - 32}{2 \cdot 16} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - \frac{1}{4}

(x - 2) (x - a) = 0

7 x^{2} - 91 x = 0

X, 2 Y^{2} - X Y + X^{2} = 1

x, 18 x^{2} + 8 y^{2} + 72 z^{2} = 72

9 x^{2} - 54 = 0

What are the solutions to the equation 16x^2-24x-7=0 ?
The solutions to the equation 16x^2-24x-7=0 are x= 7/4 ,x=-1/4
Find the zeros of 16x^2-24x-7=0
The zeros of 16x^2-24x-7=0 are x= 7/4 ,x=-1/4