What are the solutions to the equation solvefor x,y^2+2xy-x^2=0 ?

The solutions to the equation solvefor x,y^2+2xy-x^2=0 are x=-(sqrt(2)-1)y,x=(1+sqrt(2))y

Find the zeros of solvefor x,y^2+2xy-x^2=0

The zeros of solvefor x,y^2+2xy-x^2=0 are x=-(sqrt(2)-1)y,x=(1+sqrt(2))y

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solve for

x, y^{2} + 2 x y - x^{2} = 0

x = - (2 - 1) y, x = (1 + 2) y

Solution steps

y^{2} + 2 x y - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 y x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 y \pm ( 2 y ) ^{2} - 4 ( - 1 ) y ^{2}}{2 ( - 1 )}

Simplify

(2 y)^{2} - 4 (- 1) y^{2} : 22 y

x_{1, 2} = \frac{- 2 y \pm 2 2 y}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 y + 2 2 y}{2 ( - 1 )}, x_{2} = \frac{- 2 y - 2 2 y}{2 ( - 1 )}

x = \frac{- 2 y + 2 2 y}{2 ( - 1 )} : - (2 - 1) y

x = \frac{- 2 y - 2 2 y}{2 ( - 1 )} : (1 + 2) y

The solutions to the quadratic equation are:

x = - (2 - 1) y, x = (1 + 2) y

3 t^{2} - 5 t + 2 = 0

x (x + 3) = 5 x + 3

- 2 x^{2} + 10 x = 12

15 n^{2} + 41 n - 18 = 2 n

2 x^{2} + 9 x - 1 = 2 x - 7

What are the solutions to the equation solvefor x,y^2+2xy-x^2=0 ?
The solutions to the equation solvefor x,y^2+2xy-x^2=0 are x=-(sqrt(2)-1)y,x=(1+sqrt(2))y
Find the zeros of solvefor x,y^2+2xy-x^2=0
The zeros of solvefor x,y^2+2xy-x^2=0 are x=-(sqrt(2)-1)y,x=(1+sqrt(2))y