What are the solutions to the equation s^2-3s-4=0 ?

The solutions to the equation s^2-3s-4=0 are s=4,s=-1

Find the zeros of s^2-3s-4=0

The zeros of s^2-3s-4=0 are s=4,s=-1

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s^{2} - 3 s - 4 = 0

s = 4, s = - 1

Solution steps

s^{2} - 3 s - 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 4) = 5

s_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, s_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

s = \frac{- ( - 3 ) + 5}{2 \cdot 1} : 4

s = \frac{- ( - 3 ) - 5}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

s = 4, s = - 1

4 x^{2} + 6 x = - 2 x - 2

x^{2} - 6 x + 34

82 = (A + B) x^{2} + (C - B) x + (81 A - C)

5 x^{2} - 34 x = 0

9 x^{2} - 6 x + 8 = 0

What are the solutions to the equation s^2-3s-4=0 ?
The solutions to the equation s^2-3s-4=0 are s=4,s=-1
Find the zeros of s^2-3s-4=0
The zeros of s^2-3s-4=0 are s=4,s=-1