What are the solutions to the equation n^2+18n=-75 ?

The solutions to the equation n^2+18n=-75 are n=-9+sqrt(6),n=-9-sqrt(6)

Find the zeros of n^2+18n=-75

The zeros of n^2+18n=-75 are n=-9+sqrt(6),n=-9-sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} + 18 n = - 75

n = - 9 + 6, n = - 9 - 6

Decimal Notation

n = - 6.55051 \dots, n = - 11.44948 \dots

Solution steps

n^{2} + 18 n = - 75

Move

75

to the left side

n^{2} + 18 n + 75 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 75}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 75 = 26

n_{1, 2} = \frac{- 18 \pm 2 6}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 18 + 2 6}{2 \cdot 1}, n_{2} = \frac{- 18 - 2 6}{2 \cdot 1}

n = \frac{- 18 + 2 6}{2 \cdot 1} : - 9 + 6

n = \frac{- 18 - 2 6}{2 \cdot 1} : - 9 - 6

The solutions to the quadratic equation are:

n = - 9 + 6, n = - 9 - 6

(\frac{1}{16})^{\frac{1}{2}}

c^{2} - 9 c + 18

\frac{i 5}{i \frac{1}{5}}

\frac{∣ - 1 ∣}{- 1}

2 x^{2} - 7 x - 3 = 0

What are the solutions to the equation n^2+18n=-75 ?
The solutions to the equation n^2+18n=-75 are n=-9+sqrt(6),n=-9-sqrt(6)
Find the zeros of n^2+18n=-75
The zeros of n^2+18n=-75 are n=-9+sqrt(6),n=-9-sqrt(6)