What are the solutions to the equation (x-sqrt(3))^2=-10sqrt(3)+28 ?

The solutions to the equation (x-sqrt(3))^2=-10sqrt(3)+28 are x=5,x=-5+2sqrt(3)

Find the zeros of (x-sqrt(3))^2=-10sqrt(3)+28

The zeros of (x-sqrt(3))^2=-10sqrt(3)+28 are x=5,x=-5+2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 3)^{2} = - 103 + 28

x = 5, x = - 5 + 23

Decimal Notation

x = 5, x = - 1.53589 \dots

Solution steps

(x - 3)^{2} = - 103 + 28

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 103 + 28 : x = 5

Solve

x - 3 = - - 103 + 28 : x = - 5 + 23

The solutions to the quadratic equation are:

x = 5, x = - 5 + 23

33 + \frac{2 x ^{2}}{3} = 17

428 = - 0.32 q^{2} + 500

x^{2} + 7 x + 7 + 8 = 0

x^{2} + 14 x + 35 = - 5

(x) = 0.001 x^{2} - 5.98 x + 80

What are the solutions to the equation (x-sqrt(3))^2=-10sqrt(3)+28 ?
The solutions to the equation (x-sqrt(3))^2=-10sqrt(3)+28 are x=5,x=-5+2sqrt(3)
Find the zeros of (x-sqrt(3))^2=-10sqrt(3)+28
The zeros of (x-sqrt(3))^2=-10sqrt(3)+28 are x=5,x=-5+2sqrt(3)