What are the solutions to the equation y^2-18y+97=0 ?

The solutions to the equation y^2-18y+97=0 are y=9+4i,y=9-4i

Find the zeros of y^2-18y+97=0

The zeros of y^2-18y+97=0 are y=9+4i,y=9-4i

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y^{2} - 18 y + 97 = 0

y = 9 + 4 i, y = 9 - 4 i

Solution steps

y^{2} - 18 y + 97 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 97}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 97 : 8 i

y_{1, 2} = \frac{- ( - 18 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 18 ) + 8 i}{2 \cdot 1}, y_{2} = \frac{- ( - 18 ) - 8 i}{2 \cdot 1}

y = \frac{- ( - 18 ) + 8 i}{2 \cdot 1} : 9 + 4 i

y = \frac{- ( - 18 ) - 8 i}{2 \cdot 1} : 9 - 4 i

The solutions to the quadratic equation are:

y = 9 + 4 i, y = 9 - 4 i

A = x^{2} + 16 x + 64

x^{2} + 10 = 10

- 5 q + 200 = 0.5 q^{2} + 100

6 x^{2} + 2 x - 6 = 0

(x + 5)^{2} = 2 x^{2} + 6 x + 17

What are the solutions to the equation y^2-18y+97=0 ?
The solutions to the equation y^2-18y+97=0 are y=9+4i,y=9-4i
Find the zeros of y^2-18y+97=0
The zeros of y^2-18y+97=0 are y=9+4i,y=9-4i