What are the solutions to the equation 1/2 x^2-x-1=-x+1 ?

The solutions to the equation 1/2 x^2-x-1=-x+1 are x=2,x=-2

Find the zeros of 1/2 x^2-x-1=-x+1

The zeros of 1/2 x^2-x-1=-x+1 are x=2,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{2} x^{2} - x - 1 = - x + 1

x = 2, x = - 2

Solution steps

\frac{1}{2} x^{2} - x - 1 = - x + 1

Move

1

to the right side

\frac{1}{2} x^{2} - x = - x + 2

Move

x

to the left side

\frac{1}{2} x^{2} = 2

Multiply both sides by

2

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

13 t^{2} - 8 t + 1 = - 3 t^{2}

x, x^{2} + y^{2} + (z - 2)^{2} = 4

2 a x^{2} - (2 + a) b x + b^{2} = 0

x^{2} - 6 x = - 3 x + 28

x^{2} - 100 = 3 x^{2} + 96

What are the solutions to the equation 1/2 x^2-x-1=-x+1 ?
The solutions to the equation 1/2 x^2-x-1=-x+1 are x=2,x=-2
Find the zeros of 1/2 x^2-x-1=-x+1
The zeros of 1/2 x^2-x-1=-x+1 are x=2,x=-2