What are the solutions to the equation s^2+12s+936=0 ?

The solutions to the equation s^2+12s+936=0 are s=-6+30i,s=-6-30i

Find the zeros of s^2+12s+936=0

The zeros of s^2+12s+936=0 are s=-6+30i,s=-6-30i

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s^{2} + 12 s + 936 = 0

s = - 6 + 30 i, s = - 6 - 30 i

Solution steps

s^{2} + 12 s + 936 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 936}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 936 : 60 i

s_{1, 2} = \frac{- 12 \pm 60 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 12 + 60 i}{2 \cdot 1}, s_{2} = \frac{- 12 - 60 i}{2 \cdot 1}

s = \frac{- 12 + 60 i}{2 \cdot 1} : - 6 + 30 i

s = \frac{- 12 - 60 i}{2 \cdot 1} : - 6 - 30 i

The solutions to the quadratic equation are:

s = - 6 + 30 i, s = - 6 - 30 i

(2 x - 1)^{2} + 11 = 4

4 v^{2} + 9 v - 2 = 4 v

3 x^{2} + 17 x + 15 = 5

a, g (a + b) = (a + b)^{2} - 4 (a + b)

2 \cdot (x^{2} + 10) = 22

What are the solutions to the equation s^2+12s+936=0 ?
The solutions to the equation s^2+12s+936=0 are s=-6+30i,s=-6-30i
Find the zeros of s^2+12s+936=0
The zeros of s^2+12s+936=0 are s=-6+30i,s=-6-30i