What are the solutions to the equation 2250=30x-0.1x^2 ?

The solutions to the equation 2250=30x-0.1x^2 are x=150

Find the zeros of 2250=30x-0.1x^2

The zeros of 2250=30x-0.1x^2 are x=150

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2250 = 30 x - 0.1 x^{2}

x = 150

Solution steps

2250 = 30 x - 0.1 x^{2}

Multiply both sides by

10

22500 = 300 x - x^{2}

Switch sides

300 x - x^{2} = 22500

Move

22500

to the left side

300 x - x^{2} - 22500 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 300 x - 22500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 300 \pm 30 0 ^{2} - 4 ( - 1 ) ( - 22500 )}{2 ( - 1 )}

30 0^{2} - 4 (- 1) (- 22500) = 0

x_{1, 2} = \frac{- 300 \pm 0}{2 ( - 1 )}

x = \frac{- 300}{2 ( - 1 )}

\frac{- 300}{2 ( - 1 )} = 150

x = 150

The solution to the quadratic equation is:

x = 150

x^{2} - 4 x + 1 = 3

- 5 x^{2} - 3 x + 4 = 0

4 k^{2} - 22 k - 14 = 0

5^{2} + (117)^{2} = x^{2}

x^{2} - \frac{3}{2} x - \frac{16}{7} = 0

What are the solutions to the equation 2250=30x-0.1x^2 ?
The solutions to the equation 2250=30x-0.1x^2 are x=150
Find the zeros of 2250=30x-0.1x^2
The zeros of 2250=30x-0.1x^2 are x=150