What are the solutions to the equation 6x^2-10=-7x-7 ?

The solutions to the equation 6x^2-10=-7x-7 are x= 1/3 ,x=-3/2

Find the zeros of 6x^2-10=-7x-7

The zeros of 6x^2-10=-7x-7 are x= 1/3 ,x=-3/2

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6 x^{2} - 10 = - 7 x - 7

x = \frac{1}{3}, x = - \frac{3}{2}

Decimal Notation

x = 0.33333 \dots, x = - 1.5

Solution steps

6 x^{2} - 10 = - 7 x - 7

Move

7

to the left side

6 x^{2} - 3 = - 7 x

Move

7 x

to the left side

6 x^{2} - 3 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

7^{2} - 4 \cdot 6 (- 3) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 6}, x_{2} = \frac{- 7 - 11}{2 \cdot 6}

x = \frac{- 7 + 11}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 7 - 11}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{2}

10 d^{2} + d + 3 = 6

16 x^{2} - 42 x - 7 = 0

1.4 x^{2} + 8.3 x + 1 = 0

3 x^{2} - 7 x + 5 = 1

(x - 2)^{2} = 2 x - 1

What are the solutions to the equation 6x^2-10=-7x-7 ?
The solutions to the equation 6x^2-10=-7x-7 are x= 1/3 ,x=-3/2
Find the zeros of 6x^2-10=-7x-7
The zeros of 6x^2-10=-7x-7 are x= 1/3 ,x=-3/2