What are the solutions to the equation (x-1)^2-16=1 ?

The solutions to the equation (x-1)^2-16=1 are x=sqrt(17)+1,x=-sqrt(17)+1

Find the zeros of (x-1)^2-16=1

The zeros of (x-1)^2-16=1 are x=sqrt(17)+1,x=-sqrt(17)+1

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(x - 1)^{2} - 16 = 1

x = 17 + 1, x = - 17 + 1

Decimal Notation

x = 5.12310 \dots, x = - 3.12310 \dots

Solution steps

(x - 1)^{2} - 16 = 1

Move

16

to the right side

(x - 1)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 17 : x = 17 + 1

Solve

x - 1 = - 17 : x = - 17 + 1

The solutions to the quadratic equation are:

x = 17 + 1, x = - 17 + 1

6 n^{2} = - 12 n - 1

x, x^{2} y + x y = 1

6 x^{2} - x - 3 = 0

5^{2} = x^{2} + (x + 1)^{2}

12 x^{2} - 256 x + 1024 = 0

What are the solutions to the equation (x-1)^2-16=1 ?
The solutions to the equation (x-1)^2-16=1 are x=sqrt(17)+1,x=-sqrt(17)+1
Find the zeros of (x-1)^2-16=1
The zeros of (x-1)^2-16=1 are x=sqrt(17)+1,x=-sqrt(17)+1