What are the solutions to the equation 4x^2-40x+300=0 ?

The solutions to the equation 4x^2-40x+300=0 are x=5+5sqrt(2)i,x=5-5sqrt(2)i

Find the zeros of 4x^2-40x+300=0

The zeros of 4x^2-40x+300=0 are x=5+5sqrt(2)i,x=5-5sqrt(2)i

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4 x^{2} - 40 x + 300 = 0

x = 5 + 52 i, x = 5 - 52 i

Solution steps

4 x^{2} - 40 x + 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 4 \cdot 300}{2 \cdot 4}

Simplify

(- 40)^{2} - 4 \cdot 4 \cdot 300 : 402 i

x_{1, 2} = \frac{- ( - 40 ) \pm 40 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 40 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 40 ) - 40 2 i}{2 \cdot 4}

x = \frac{- ( - 40 ) + 40 2 i}{2 \cdot 4} : 5 + 52 i

x = \frac{- ( - 40 ) - 40 2 i}{2 \cdot 4} : 5 - 52 i

The solutions to the quadratic equation are:

x = 5 + 52 i, x = 5 - 52 i

(\frac{x}{8})^{2} + 12 = x

x^{2} + 7 = 5 x + 1

x^{2} - \frac{11}{35} x - \frac{2}{7} = 0

x^{2} - x + 8 = - 10 x

x, x^{2} + y^{2} + 6 x - 2 y + 16 = 0

What are the solutions to the equation 4x^2-40x+300=0 ?
The solutions to the equation 4x^2-40x+300=0 are x=5+5sqrt(2)i,x=5-5sqrt(2)i
Find the zeros of 4x^2-40x+300=0
The zeros of 4x^2-40x+300=0 are x=5+5sqrt(2)i,x=5-5sqrt(2)i