What are the solutions to the equation (x-2)^2-1=3 ?

The solutions to the equation (x-2)^2-1=3 are x=4,x=0

Find the zeros of (x-2)^2-1=3

The zeros of (x-2)^2-1=3 are x=4,x=0

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(x - 2)^{2} - 1 = 3

x = 4, x = 0

Solution steps

(x - 2)^{2} - 1 = 3

Move

1

to the right side

(x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

9 x^{2} + 3 x + 1 = 4 x^{2}

4 x + x^{2} = - 5

x, y (x - 1) (x - 3) = 4

\frac{( x ^{2} + 2 )}{2} = \frac{( 7 x - 5 )}{3}

11 t^{2} - 6 t + 1 = 2 t^{2}

What are the solutions to the equation (x-2)^2-1=3 ?
The solutions to the equation (x-2)^2-1=3 are x=4,x=0
Find the zeros of (x-2)^2-1=3
The zeros of (x-2)^2-1=3 are x=4,x=0