What are the solutions to the equation 3x^2+7x-3=3x+1 ?

The solutions to the equation 3x^2+7x-3=3x+1 are x= 2/3 ,x=-2

Find the zeros of 3x^2+7x-3=3x+1

The zeros of 3x^2+7x-3=3x+1 are x= 2/3 ,x=-2

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3 x^{2} + 7 x - 3 = 3 x + 1

x = \frac{2}{3}, x = - 2

Decimal Notation

x = 0.66666 \dots, x = - 2

Solution steps

3 x^{2} + 7 x - 3 = 3 x + 1

Move

1

to the left side

3 x^{2} + 7 x - 4 = 3 x

Move

3 x

to the left side

3 x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 4) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 3}, x_{2} = \frac{- 4 - 8}{2 \cdot 3}

x = \frac{- 4 + 8}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 4 - 8}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 2

x^{2} + 2 x = 3 - 2 x

x^{2} + 2 x = 0

\frac{x ^{2}}{4} = 4

4 z^{2} + 12 z + 11 = 0

3 p = 10 - p^{2}

What are the solutions to the equation 3x^2+7x-3=3x+1 ?
The solutions to the equation 3x^2+7x-3=3x+1 are x= 2/3 ,x=-2
Find the zeros of 3x^2+7x-3=3x+1
The zeros of 3x^2+7x-3=3x+1 are x= 2/3 ,x=-2