What are the solutions to the equation (4x-3)^2-(x-1)(x-9)=0 ?

The solutions to the equation (4x-3)^2-(x-1)(x-9)=0 are x= 14/15 ,x=0

Find the zeros of (4x-3)^2-(x-1)(x-9)=0

The zeros of (4x-3)^2-(x-1)(x-9)=0 are x= 14/15 ,x=0

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(4 x - 3)^{2} - (x - 1) (x - 9) = 0

x = \frac{14}{15}, x = 0

Decimal Notation

x = 0.93333 \dots, x = 0

Solution steps

(4 x - 3)^{2} - (x - 1) (x - 9) = 0

Expand

(4 x - 3)^{2} - (x - 1) (x - 9) : 15 x^{2} - 14 x

15 x^{2} - 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

(- 14)^{2} - 4 \cdot 15 \cdot 0 = 14

x_{1, 2} = \frac{- ( - 14 ) \pm 14}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 14}{2 \cdot 15}, x_{2} = \frac{- ( - 14 ) - 14}{2 \cdot 15}

x = \frac{- ( - 14 ) + 14}{2 \cdot 15} : \frac{14}{15}

x = \frac{- ( - 14 ) - 14}{2 \cdot 15} : 0

The solutions to the quadratic equation are:

x = \frac{14}{15}, x = 0

x^{2} + 10 x + 28

3 z^{2} - 8 z + 4 = 5 z

\frac{y ^{2}}{4} = \frac{3 y + 4}{4}

x^{2} + 8 x - 11 = 6 x - 8

y^{2} - 2 = - y

What are the solutions to the equation (4x-3)^2-(x-1)(x-9)=0 ?
The solutions to the equation (4x-3)^2-(x-1)(x-9)=0 are x= 14/15 ,x=0
Find the zeros of (4x-3)^2-(x-1)(x-9)=0
The zeros of (4x-3)^2-(x-1)(x-9)=0 are x= 14/15 ,x=0